Electrostatics Question 231

Question: If on the concentric hollow spheres of radii r and R(>r) the charge Q is distributed such that their surface densities are same then the potential at their common centre is [IIT 1981; MP PMT 2003]

Options:

A) Q(R2+r2)4πε0(R+r)

B) QRR+r

C) Zero

D) Q(R+r)4πε0(R2+r2)

Show Answer

Answer:

Correct Answer: D

Solution:

q1+q2=Q

and q14πr2=q24πR2 (given) q1=Qr2R2+r2

and q2=QR2R2+r2

Potential at common centre 14πε0[Qr2(R2+r2)r+QR2(R2+r2)R]=Q(R+r)4πε0(R2+r2)



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