Electrostatics Question 222

Question: Two charges of equal magnitudes and at a distance r exert a force F on each other. If the charges are halved and distance between them is doubled, then the new force acting on each charge is [DCE 2004]

Options:

A) F / 8

B) F / 4

C) 4 F

D) F / 16

Show Answer

Answer:

Correct Answer: D

Solution:

$ F=k.\frac{Q^{2}}{r^{2}} $ . If Q is halved, r is doubled then $ F\to \frac{1}{16}\text{times} $



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