Electrostatics Question 210

Question: Two point charges placed at a certain distance r in air exert a force F on each other. Then the distance r’ at which these charges will exert the same force in a medium of dielectric constant k is given by [EAMCET 1990; MP PMT 2001]

Options:

A) r

B) r/k

C) $ r/\sqrt{k} $

D) $ r\sqrt{k} $

Show Answer

Answer:

Correct Answer: C

Solution:

$ F=F’ $ or $ \frac{Q _{1}Q _{2}}{4\pi {\varepsilon _{0}}r^{2}}=\frac{Q _{1}Q _{2}}{4\pi {\varepsilon _{0}}r{{’}^{2}}K}\Rightarrow r’=\frac{r}{\sqrt{K}} $



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