Electrostatics Question 183
Question: A force $ F $ acts between sodium and chlorine ions of salt (sodium chloride) when put $ 1cm $ apart in air. The permittivity of air and dielectric constant of water are $ {\varepsilon _{0}} $ and $ K $ respectively. When a piece of salt is put in water electrical force acting between sodium and chlorine ions $ 1cm $ apart is [MP PET 1995]
Options:
A) $ \frac{F}{K} $
B) $ \frac{FK}{{\varepsilon _{0}}} $) $ \frac{F}{K{\varepsilon _{0}}} $
D) $ \frac{F{\varepsilon _{0}}}{K} $
Show Answer
Answer:
Correct Answer: A
Solution:
When put 1 cm apart in air, the force between Na and Cl ions = F. When put in water, the force between Na and Cl ions $ =\frac{F}{K} $
