Electrostatics Question 178

Question: ABC is a right angled triangle in which AB=3cm and BC=4cm . And Ð ABC = p/2. The three charges +15, +12 and 20e.s.u. are placed respectively on A , B and C . The force acting on B is

Options:

A) 125 dynes

B) 35 dynes

C) 25 dynes

D) Zero

Show Answer

Answer:

Correct Answer: C

Solution:

Net force on B Fnet=FA2+FC2

FA=15×12(3)2=20dyne , FC=12×20(4)2=15dyne

therefore Fnet=FA2+FC2=(20)2+(15)2=25dyne



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