Electrostatics Question 134

Question: 64 drops of mercury each charged to a potential of $ 10V $ . They are combined to form one bigger drop. The potential of this drop will be (Assume all the drops to be spherical) [MP PET 2003]

Options:

A) 160 V

B) 80 V

C) 10 V

D) 640 V

Show Answer

Answer:

Correct Answer: A

Solution:

$ V={{n}^{2/3}}v={{(64)}^{2/3}}\times 10=160volt $



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