Electrostatics Question 133

Question: The work done in placing a charge of $ 8\times {{10}^{-18}} $ coulomb on a condenser of capacity 100 micro-farad is [AIEEE 2003]

Options:

A) $ 32\times {{10}^{-32}}Joule $

B) $ 16\times {{10}^{-32}}Joule $

C) $ 3.1\times {{10}^{-26}}Joule $

D) $ 4\times {{10}^{-10}}Joule $

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Answer:

Correct Answer: A

Solution:

$ W=\frac{Q^{2}}{2C}=\frac{{{(8\times {{10}^{-18}})}^{2}}}{2\times 100\times {{10}^{-6}}}=32\times {{10}^{-32}}J $



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