Electrostatics Question 130

Question: Capacitance of a parallel plate capacitor becomes 4/3 times its original value if a dielectric slab of thickness t = d/2 is inserted between the plates (d is the separation between the plates). The dielectric constant of the slab is [KCET 2003]

Options:

A) 8

B) 4

C) 6

D) 2

Show Answer

Answer:

Correct Answer: D

Solution:

Cair=ε0Ad , with dielectric slab C¢= ε0A(dt+tK)

Given C=43C

ε0A(dt+tK)=43×ε0Ad

K=4t4td=4(d/2)4[(d/2)d]=2



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