Electrostatics Question 123

Question: 64 small drops of mercury, each of radius r and charge q coalesce to form a big drop. The ratio of the surface density of charge of each small drop with that of the big drop is [KCET 2002]

Options:

A) 1 : 64

B) 64 : 1

C) 4 : 1

D) 1 : 4

Show Answer

Answer:

Correct Answer: D

Solution:

σsmallσBig=qQ×R2r2=q(nq)×(n1/3r)2r2

=n1/3=(64)1/3=14



NCERT Chapter Video Solution

Dual Pane