Electrostatics Question 114

Question: A charge of $ 40\mu C $ is given to a capacitor having capacitance $ C=10\mu F $ . The stored energy in ergs is [CPMT 2002]

Options:

A) $ 80\times {{10}^{-6}} $

B) 800

C) 80

D) 8000

Show Answer

Answer:

Correct Answer: B

Solution:

$ U=\frac{Q^{2}}{2C}=\frac{{{(40\times {{10}^{-6}})}^{2}}}{2\times {{10}^{-6}}\times 10}=\frac{16\times {{10}^{-10}}}{2\times {{10}^{-5}}}=8\times {{10}^{-5}}J $

$ =8\times {{10}^{-5}}\times 10^{7}=800erg $



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