Electronic Devices Question 6
Question: A common emitter amplifier is designed with NPN transistor (a = 0.99). The input impedance is 1 KW and load is 10 KW. The voltage gain will be
[CPMT 1996]
Options:
A) 9.9
B) 99
C) 990
D) 9900
Show Answer
Answer:
Correct Answer: C
Solution:
Voltage gain = b x Resistance gain
Resistance gain
Therefore Voltage gain = 99 x 10 = 990.
