SATHEE: Electronic Devices Question 44

Electronic Devices Question 44

Question: Let $n_{P}$ and $n_{e}$ be the number of holes and conduction electrons respectively in a semiconductor. Then

[MP PET 1995]

Options:

A) $n_{P} > n_{e}$ in an intrinsic semiconductor

B) $n_{P} = n_{e}$ in an extrinsic semiconductor

C) $n_{P} = n_{e}$ in an intrinsic semiconductor

D) $n_{e} > n_{P}$ in an intrinsic semiconductor

Show Answer

Answer:

Correct Answer: C

Solution:

In intrinsic semiconductors, the creation or liberation of one free electron by the thermal energy has created one hole.

Thus in intrinsic semiconductors ne = nh

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Electronic Devices Question 44

Question: Let nP and ne be the number of holes and conduction electrons respectively in a semiconductor. Then

Options:

Answer:

Solution:

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Question: Let $n_{P}$ and $n_{e}$ be the number of holes and conduction electrons respectively in a semiconductor. Then