SATHEE: Electronic Devices Question 29

Electronic Devices Question 29

Question: In a semiconductor, the concentration of electrons is $8 \times 10^{14} / c m^{3}$ and that of the holes is $5 \times 10^{12} c m^{3} .$ The semiconductor is

[MP PMT 1997; RPET 1999; Kerala PET 2002]

Options:

A) P-type

B) N-type

C) Intrinsic

D) PNP-type

Show Answer

Answer:

Correct Answer: B

Solution:

Since ne > nh; the semiconductor is N-type.

Play Store

App Store

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Electronic Devices Question 29

Question: In a semiconductor, the concentration of electrons is 8×1014/cm3 and that of the holes is 5×1012cm3. The semiconductor is

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu

Question: In a semiconductor, the concentration of electrons is $8 \times 10^{14} / c m^{3}$ and that of the holes is $5 \times 10^{12} c m^{3} .$ The semiconductor is