Electronic Devices Question 271

Question: The truth table shown in figure is for [Pb. CET 1998]
A 0 0 1 1
B 0 1 0 1
Y 1 0 0 1

Options:

A) XOR

B) AND

C) XNOR

D) OR

Show Answer

Answer:

Correct Answer: C

Solution:

For XNOR gate Y=A¯B¯+AB i.e.

0¯.0¯+0.0=1.1+0.0=1+0=1

0¯.1¯+0.1=1.0+0.1=0+0=0

1¯.0¯+1.0=0.1+1.0=0+0=0

1¯.1¯+1.1=0.0+1.1=0+1=1



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