SATHEE: Electronic Devices Question 263

Electronic Devices Question 263

Question: For a triode m = 64 and gm =1600 m mho. It is used as an amplifier and an input signal of 1V (rms) is applied. The signal power in the load of 40 kW will be

Options:

A) 23.5 mW

B) 48.7 mW

C) 25.6 mW

D) None of these

Show Answer

Answer:

Correct Answer: C

Solution:

$r_{p} = \frac{μ}{g_{m}} = \frac{64}{1600 \times 10^{- 6}} = 4 \times 10^{4} Ω$

Voltage gain $A_{v} = \frac{μ}{1 + \frac{r_{p}}{R_{L}}} = \frac{64}{1 + \frac{4 \times 10^{4}}{40 \times 10^{3}}} = 32$

Output signal voltage $V_{0} = A_{v} \times V_{i} = 32 \times 1 = 32 V (r . m . s .)$

Signal power in load $= \frac{V_{0}^{2}}{R_{L}} = \frac{{(32)}^{2}}{40 \times 10^{3}} = 25.6 m W$

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Electronic Devices Question 263

Question: For a triode m = 64 and gm =1600 m mho. It is used as an amplifier and an input signal of 1V (rms) is applied. The signal power in the load of 40 kW will be

Options:

Answer:

Solution:

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