Electronic Devices Question 261

Question: A triode whose mutual conductance is 2.5 m A/volt and anode resistance is 20 kilo ohm, is used as an amplifier whose amplification is 10. The resistance connected in plate circuit will be

[MP PET 1989; RPMT 1998]

Options:

A) 1 kW

B) 5 kW

C) 10 kW

D) 20 kW

Show Answer

Answer:

Correct Answer: B

Solution:

μ=rP×gm=20×2.5=50

From A=μRLrP+RL

Therefore rP+RL=μRLA=50RL10=5RL

Therefore 4RL=rpRL=rp4=204=5kΩ



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