Electronic Devices Question 255

Question: The relation between Ip and Vp for a triode is $ I _{p}=(0.125V _{p}-7.5)mA $ Keeping the grid potential constant at 1V, the value of rp will be

Options:

A) 8 kW

B) 4 kW

C) 2 kW

D) 8 kW

Show Answer

Answer:

Correct Answer: D

Solution:

$ i _{p}=[0.125V _{p}-7.5]\times {{10}^{-3}}amp $

Differentiating this equation w.r.t.

V­p $ \frac{\Delta i _{p}}{\Delta V _{p}}=0.125\times {{10}^{-3}} $ or $ \frac{1}{r _{p}}=0.125\times {{10}^{-3}} $

Therefore $ r _{p}=8k\Omega $



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