Electronic Devices Question 250

Question: For the transistor circuit shown below, if b = 100, voltage drop between emitter and base is 0.7 V then value of VCE will be

Options:

A) 10 V

B) 5 V

C) 13 V

D) 0 V

Show Answer

Answer:

Correct Answer: C

Solution:

ib=5−0.78.6=0.5mA

Therefore Ic=βIb=100×0.5mA

By using VCE=VCC−IcRL=18−50×10−3×100=13V

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