Electronic Devices Question 250

Question: For the transistor circuit shown below, if b = 100, voltage drop between emitter and base is 0.7 V then value of VCE will be

Options:

A) 10 V

B) 5 V

C) 13 V

D) 0 V

Show Answer

Answer:

Correct Answer: C

Solution:

$ i _{b}=\frac{5-0.7}{8.6}=0.5mA $

Therefore $ I _{c}=\beta I _{b}=100\times 0.5mA $

By using $ V _{CE}=V _{CC}-I _{c}R _{L}=18-50\times {{10}^{-3}}\times 100=13V $



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