Electronic Devices Question 241

Question: A transistor is used as an amplifier in CB mode with a load resistance of 5 k W the current gain of amplifier is 0.98 and the input resistance is 70 W, the voltage gain and power gain respectively are

[Pb. PET 2003]

Options:

A) 70, 68.6

B) 80, 75.6

C) 60, 66.6

D) 90, 96.6

Show Answer

Answer:

Correct Answer: A

Solution:

In common base mode a = 0.98, R = 5 kW, Rin = 70W

voltage gain $ A _{v}=\alpha \times \frac{R}{R _{in}}=0.98\times \frac{5\times 10^{3}}{70}=70 $

Power gain = Current gain - Voltage gain = 0.98 - 70 = 68.6



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