Electronic Devices Question 236

Question: In semiconductor the concentrations of electrons and holes are 8×1018/m3 and 5×1018/mrespectively. If the mobilities of electrons and hole are 2.3 m2/volt-sec and 0.01 m2/volt-sec respectively, then semiconductor is

Options:

A) N-type and its resistivity is 0.34 ohm-metre

B) P-type and its resistivity is 0.034 ohm-metre

C) N-type and its resistivity is 0.034 ohm-metre

D) P-type and its resistivity is 3.40 ohm-metre

Show Answer

Answer:

Correct Answer: A

Solution:

ne=8×1018/m3,  nh=5×1018/m3

μe=2.3m2voltsec,  μh=0.01m2voltsec

ne>nh so semiconductor is N-type

Also conductivity σ=1Resistivity(ρ)=e(neμe+nhμh)

Therefore 1ρ=1.6×1019[8×1018×2.3+5×1018×0.01]

Therefore r = 0.34 W-m.



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