Electronic Devices Question 233

Question: For a transistor amplifier in common emitter configuration for load impedance of 1 kW (hfe = 50 and hoe = 25 mA/V) the current gain is

[AIEEE 2004]

Options:

A) - 5.2

B) - 15.7

C) - 24.8

D) - 48.78

Show Answer

Answer:

Correct Answer: D

Solution:

In common emitter configuration current gain Ai=hfe1+hoeRL=501+25×106×103 = - 48.78.



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