Electronic Devices Question 231

Question: Current in the circuit will be

[CBSE PMT 2001]

Options:

A) $ \frac{5}{40}A $

B) $ \frac{5}{50}A $

C) $ \frac{5}{10}A $

D) $ \frac{5}{20}A $

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Answer:

Correct Answer: B

Solution:

The diode in lower branch is forward biased and diode in upper branch is reverse biased

$ i=\frac{5}{20+30}=\frac{5}{50}A $ .



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