SATHEE: Electronic Devices Question 199

Electronic Devices Question 199

Question: A triode has a mutual conductance of $2 \times 10^{- 3} m h o$ and an amplification factor of 50. The anode is connected through a resistance of $25 \times 10^{3}$ ohms to a 250 volts supply. The voltage gain of this amplifier is

[MP PMT 1989]

Options:

A) 50

B) 25

C) 100

D) 12.5

Show Answer

Answer:

Correct Answer: B

Solution:

Using $A_{V} = \frac{μ}{1 + \frac{r_{p}}{R_{L}}}$ and $μ = r_{p} \times g_{m}$
$\Rightarrow r_{p} = \frac{μ}{g_{m}} = \frac{50}{2 \times 10^{- 3}} = 25 \times 10^{3} Ω$
$∴ A_{v} = \frac{50}{1 + \frac{25 \times 10^{3}}{25 \times 10^{3}}} = 25.$

Electronic Devices Question 199

Question: A triode has a mutual conductance of $2 \times 10^{- 3} m h o$ and an amplification factor of 50. The anode is connected through a resistance of $25 \times 10^{3}$ ohms to a 250 volts supply. The voltage gain of this amplifier is

Options:

Answer:

Solution:

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Electronic Devices Question 199

Question: A triode has a mutual conductance of 2×10−3mho and an amplification factor of 50. The anode is connected through a resistance of 25×103 ohms to a 250 volts supply. The voltage gain of this amplifier is

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: A triode has a mutual conductance of $2 \times 10^{- 3} m h o$ and an amplification factor of 50. The anode is connected through a resistance of $25 \times 10^{3}$ ohms to a 250 volts supply. The voltage gain of this amplifier is