Electronic Devices Question 174

Question: The nearest distance between two atoms in case of a bcc lattice is equal to

[J & K CET 2004]

Options:

A) $ a\frac{\sqrt{2}}{3} $

B) $ a\frac{\sqrt{3}}{2} $

C) $ q\sqrt{3} $

D) $ \frac{a}{\sqrt{2}} $

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Answer:

Correct Answer: B

Solution:

The nearest distance between two atoms in a bcc lattice = 2 (atomic radius) $ =2\times ( \frac{\sqrt{3}a}{4} )=\frac{\sqrt{3}a}{2} $



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