SATHEE: Electronic Devices Question 16

Electronic Devices Question 16

Question: The relation between a and b parameters of current gains for a transistors is given by

[Pb. PET 2000]

Options:

A) $α = \frac{β}{1 - β}$

B) $α = \frac{β}{1 + β}$

C) $α = \frac{1 - β}{β}$

D) $α = \frac{1 + β}{β}$

Show Answer

Answer:

Correct Answer: B

Solution:

$i_{e} = i_{b} + i_{c}$
$\Rightarrow \frac{i_{e}}{i_{c}} = \frac{i_{b}}{i_{c}} + 1$
$\Rightarrow \frac{1}{α} = \frac{1}{β} + 1$
$\Rightarrow α = \frac{β}{(1 + β)}$ .

Electronic Devices Question 16

Question: The relation between a and b parameters of current gains for a transistors is given by

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Electronic Devices Question 16

Question: The relation between a and b parameters of current gains for a transistors is given by

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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