Electronic Devices Question 16

Question: The relation between a and b parameters of current gains for a transistors is given by

[Pb. PET 2000]

Options:

A) $ \alpha =\frac{\beta }{1-\beta } $

B) $ \alpha =\frac{\beta }{1+\beta } $

C) $ \alpha =\frac{1-\beta }{\beta } $

D) $ \alpha =\frac{1+\beta }{\beta } $

Show Answer

Answer:

Correct Answer: B

Solution:

$ i _{e}=i _{b}+i _{c} $
$ \Rightarrow \frac{i _{e}}{i _{c}}=\frac{i _{b}}{i _{c}}+1 $
$ \Rightarrow \frac{1}{\alpha }=\frac{1}{\beta }+1 $
$ \Rightarrow \alpha =\frac{\beta }{(1+\beta )} $ .



NCERT Chapter Video Solution

Dual Pane