Electro Magnetic Induction And Alternating Currents Question 90

Question: The peak value of an alternating e.m.f. E is given by E=E0cosω,t is 10 volts and its frequency is 50 Hz. At time t=1600sec , the instantaneous e.m.f. is [MP PMT 1990; MP PET 2004]

Options:

A) 10 V

B) 53,V

C) 5 V

D) 1 V

Show Answer

Answer:

Correct Answer: B

Solution:

E=E0cosωt=E0cos2πtT =10cos2π×50×1600=10 cosπ6 =53 volt.



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