Electro Magnetic Induction And Alternating Currents Question 62

Question: Reactance of a capacitor of capacitance $ C\mu F $ for ac frequency $ \frac{400}{\pi } $ Hz is $ 25\Omega $ . The value C is [MH CET 2002]

Options:

A) $ 50\mu F $

B) $ 25\mu F $

C) $ 100\mu F $

D) $ 75\mu F $

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Answer:

Correct Answer: A

Solution:

$ X_{C}=\frac{1}{2\pi \nu C},\Rightarrow C=\frac{1}{2\pi \nu X_{C}}=\frac{1}{2\times \pi \times \frac{400}{\pi }\times 25}=50\mu F $



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