Electro Magnetic Induction And Alternating Currents Question 581

Question: Energy stored in a coil of self inductance 40mH carrying a steady current of 2 A is [Kerala (Engg.) 2001]

Options:

A) 0.8 J

B) 8 J

C) 0.08 J

D) 80 J

Show Answer

Answer:

Correct Answer: C

Solution:

U=12Li2⇒U=12×40×10−3×(2)2=0.08J

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