Electro Magnetic Induction And Alternating Currents Question 558

Question: The energy stored in a 50 mH inductor carrying a current of 4 A will be [MP PET 1999]

Options:

A) 0.4 J

B) 4.0 J

C) 0.8 J

D) 0.04 J

Show Answer

Answer:

Correct Answer: A

Solution:

U=12Li2=12×(50×103)×(4)2 =400×103=0.4J



NCERT Chapter Video Solution

Dual Pane