Electro Magnetic Induction And Alternating Currents Question 557

Question: The mutual inductance between a primary and secondary circuits is 0.5 H. The resistances of the primary and the secondary circuits are 20 ohms and 5 ohms respectively. To generate a current of 0.4 A in the secondary, current in the primary must be changed at the rate of [MP PMT 1997]

Options:

A) 4.0 A/s

B) 16.0 A/s

C) 1.6 A/s

D) 8.0 A/s

Show Answer

Answer:

Correct Answer: A

Solution:

e2=Mdi1dti2R2=Mdi1dt0.4×5=0.5×di1dt
di1dt=4 A/sec.



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