Electro Magnetic Induction And Alternating Currents Question 550
Question: The number of turns of primary and secondary coils of a transformer are 5 and 10 respectively and the mutual inductance of the transformer is 25 henry. Now the number of turns in the primary and secondary of the transformer are made 10 and 5 respectively. The mutual inductance of the transformer in henry will be [MP PET 1995]
Options:
A) 6.25
B) 12.5
C) 25
D) 50
Show Answer
Answer:
Correct Answer: C
Solution:
$ M=\frac{{\mu_{0}}N_{1}N_{2}A}{l} $