Electro Magnetic Induction And Alternating Currents Question 546
Question: The current flowing in a coil of self inductance 0.4 mH is increased by 250 mA in 0.1 sec. The e.m.f. induced will be [MP PMT 1994]
Options:
A) + 1 V
B) ? 1 V
C) + 1 mV
D) ? 1 mV
Show Answer
Answer:
Correct Answer: D
Solution:
$ e=-L\frac{di}{dt}=-0.4\times {{10}^{-3}}\times \frac{250\times {{10}^{-3}}}{0.1}=-1\ mV $
