Electro Magnetic Induction And Alternating Currents Question 534
Question: A coil of wire of a certain radius has 600 turns and a self inductance of 108 mH. The self inductance of a 2nd similar coil of 500 turns will be [MP PMT 1990]
Options:
A) 74 mH
B) 75 mH
C) 76 mH
D) 77 mH
Show Answer
Answer:
Correct Answer: B
Solution:
$ \frac{L_{B}}{L_{A}}={{( \frac{n_{B}}{n_{A}} )}^{2}}\Rightarrow L_{B}={{( \frac{500}{600} )}^{2}}\times 108=75\ mH $
