Electro Magnetic Induction And Alternating Currents Question 522

Question: The current passing through a choke coil of 5 henry is decreasing at the rate of 2 ampere/sec. The e.m.f. developing across the coil is [CPMT 1982; MP PMT 1990; AIIMS 1997; MP PET 1999]

Options:

A) 10 V

B) ? 10 V

C) 2.5 V

D) ? 2.5 V

Show Answer

Answer:

Correct Answer: A

Solution:

Given $ \frac{di}{dt}=2A/sec.,\ L=5\ H $
$ \therefore \ e=L\frac{di}{dt}=5\times 2=10,V $



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