SATHEE: Electro Magnetic Induction And Alternating Currents Question 516

Electro Magnetic Induction And Alternating Currents Question 516

Question: There are three wire MO, NO and PQ, wires MO and NO are fixed and perpendicular to each other. Wire PQ moves with a constant velocity v as and resistance per unit length of each wire is $λ$ and magnetic field exists perpendicular and inside the paper then. Which of the following is wrong?

Options:

A) current in loop is anticlockwise

B) magnitude of current in the loop is $\frac{B v}{λ (\sqrt{2} + 1)}$

C) current in the loop is independent of time.

D) magnitude of current decreases as time increases.

Show Answer

Answer:

Correct Answer: D

Solution:

$ϕ = B A = \frac{B}{2} \frac{x}{\sqrt{2}} \frac{x}{\sqrt{2}}$

$ε = \frac{d ϕ}{d t} = \frac{2 x}{4} \frac{d x}{d t} B = \frac{x}{2} B v$

$ε = \frac{d ϕ}{d t} = \frac{2 x}{4} \frac{d x}{d t} B = \frac{x}{2} B \frac{d (2 y)}{d t}$

$i = \frac{x B v}{2 λ (x + \sqrt{2} x)} = \frac{B v}{λ (1 + \sqrt{2})}$

Play Store

App Store

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Electro Magnetic Induction And Alternating Currents Question 516

Question: There are three wire MO, NO and PQ, wires MO and NO are fixed and perpendicular to each other. Wire PQ moves with a constant velocity v as and resistance per unit length of each wire is λ and magnetic field exists perpendicular and inside the paper then. Which of the following is wrong?

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu