Electro Magnetic Induction And Alternating Currents Question 491
Question: A small square loop of wire of side $ \ell $ is placed inside a large square loop of wire of side $ L(L>\ell ) $ .The loop are coplanar and their centre coincide. The mutual inductance of the system is proportional to
Options:
A) $ \ell /L $
B) $ {{\ell }^{2}}/L $
C) $ L/\ell $
D) $ L^{2}/\ell $
Show Answer
Answer:
Correct Answer: B
Solution:
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$ {\phi_{total}}={B_{l\arg e}}A_{small}=\frac{{\mu_{0}}}{4\pi }\frac{i}{L/2}(2\sin ,45^{o})\times {{\ell }^{2}} $
On comparing with $ {\phi_{total}}=Mi $ , we get $ M\propto \frac{{{\ell }^{2}}}{L} $
