Electro Magnetic Induction And Alternating Currents Question 49
Question: An LCR circuit contains R = 50 W , L = 1 mH and C = 0.1 mF. The impedance of the circuit will be minimum for a frequency of [Bihar MEE 1995]
Options:
A) $ \frac{10^{5}}{2\pi }{{s}^{-1}} $
B) $ \frac{10^{6}}{2\pi }{{s}^{-1}} $
C) $ 2\pi \times 10^{5}{{s}^{-1}} $
D) $ 2\pi \times 10^{6}{{s}^{-1}} $
Show Answer
Answer:
Correct Answer: A
Solution:
Impedance of LCR circuit will be minimum at resonant frequency so $ {\nu_{0}}=\frac{1}{2\pi \sqrt{LC}} $ $ =\frac{1}{2\pi \sqrt{1\times {{10}^{-3}}\times 0.1\times {{10}^{-6}}}} $ $ =\frac{10^{5}}{2\pi }Hz $
