Electro Magnetic Induction And Alternating Currents Question 489

Question: A varying current in a coil changes from 10A to zero in 0.5 sec. If the average e.m.f induced in the coil is 220V, the self-inductance of the coil is

Options:

A) 5 H

B) 6 H

C) 11 H

D) 12 H

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Answer:

Correct Answer: C

Solution:

  • Initial current

    (I1)=10A ;

    Final current (I2)=0 ;

    Time (t) = 0.5 sec and induced e.m.f. (ε)=220 V. Induced e.m.f. (ε)

    =LdIdt=L(I2I1)t=L(010)0.5=20L Or,

    L=22020=11H [where L = Self inductance of coil]



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