Electro Magnetic Induction And Alternating Currents Question 487

Question: What is the self-inductance of a coil which produces 5V when the current changes from 3 ampere to 2 ampere in one millisecond?

Options:

A) 5000 henry

B) 5 milli-henry

C) 50 henry

D) 5 henry

Show Answer

Answer:

Correct Answer: B

Solution:

  • $ L=\frac{e}{\frac{di}{dt}}=\frac{edt}{di}=\frac{5\times {{10}^{-3}}}{(3-2)}H=5mH $


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