Electro Magnetic Induction And Alternating Currents Question 487
Question: What is the self-inductance of a coil which produces 5V when the current changes from 3 ampere to 2 ampere in one millisecond?
Options:
A) 5000 henry
B) 5 milli-henry
C) 50 henry
D) 5 henry
Show Answer
Answer:
Correct Answer: B
Solution:
- $ L=\frac{e}{\frac{di}{dt}}=\frac{edt}{di}=\frac{5\times {{10}^{-3}}}{(3-2)}H=5mH $
