Electro Magnetic Induction And Alternating Currents Question 48

Question: A 220 V, 50 Hz ac source is connected to an inductance of 0.2 H and a resistance of 20 ohm in series. What is the current in the circuit [MNR 1998; JIPMER 2001, 02]

Options:

A) 10 A

B) 5 A

C) 33.3 A

D) 3.33 A

Show Answer

Answer:

Correct Answer: D

Solution:

$ i=\frac{220}{\sqrt{{{(20)}^{2}}+{{(2\times \pi \times 50\times 0.2)}^{2}}}} $ $ =\frac{220}{66}=3.33,A $



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