Electro Magnetic Induction And Alternating Currents Question 48

Question: A 220 V, 50 Hz ac source is connected to an inductance of 0.2 H and a resistance of 20 ohm in series. What is the current in the circuit [MNR 1998; JIPMER 2001, 02]

Options:

A) 10 A

B) 5 A

C) 33.3 A

D) 3.33 A

Show Answer

Answer:

Correct Answer: D

Solution:

i=220(20)2+(2×π×50×0.2)2 =22066=3.33,A



NCERT Chapter Video Solution

Dual Pane