Electro Magnetic Induction And Alternating Currents Question 465
Question: A sliding wire of length 0.25 m and having a resistance of $ 0.5\Omega $ moves along conducting guiding rails AB and CD with a uniform speed of 4 m/s. A magnetic field of 0.5 T exists normal to the plane of ABCD directed into the page. The guides are short -circuited with resistances of 4 and $ 2,\Omega $ as shown. The current through the sliding wire is:
Options:
A) 0.27 A
B) 0.37 A
C) 1.0 A
D) 0.72A
Show Answer
Answer:
Correct Answer: A
Solution:
-
The induced emf across the sliding wire
$ e=Bv\ell =0.5\times 4\times 0.25=0.5,V $
The effective circuit is .
The equivalent resistance of the circuit
$ r=\frac{4\times 2}{4+2}+0.5=1.83\Omega $
Now, $ i=\frac{V}{R}=\frac{0.5}{1.83}=0.27,A $
