Electro Magnetic Induction And Alternating Currents Question 461

Question: A flexible wire loop in the shape of a circle has radius that grown linearly with time. There is a magnetic field perpendicular to the plane of the loop that has a magnitude inversely proportional to the distance from the center of the loop, $ B(r)\propto \frac{1}{r} $ .How does the emf E vary with time?

Options:

A) $ E\propto t^{2} $

B) $ E\propto t $

C) $ E\propto \sqrt{t} $

D) E is constant

Show Answer

Answer:

Correct Answer: D

Solution:

  • Let radius of the loop is r at any time t and in further time dt, radius increases by dr.

    The change in flux:

    $ d\phi =(2\pi rdr)B $
    $ \Rightarrow e=\frac{d\phi }{dt}=2\pi r( \frac{dr}{dt} )\frac{k}{r} $
    $ \Rightarrow ,e=2\pi ck $ (constant) $ [ \because \frac{dr}{dt}=c,,B=\frac{k}{r} ] $

    The change in flux: $ d\phi =(2\pi rdr)B $



NCERT Chapter Video Solution

Dual Pane