Electro Magnetic Induction And Alternating Currents Question 458
Question: a conducting loop consisting of half circle of area $ A=0.06,m^{2} $ and three straight segments. The half circle lies in a uniform changing magnetic field $ B=4r^{2}+2t+5 $ (SI unit), where t is the time in second. An ideal battery E=2V is connected as shown and the total resistance of the wire is $ 2\Omega $ . The net current in the loop is at t=5 second is:
Options:
A) 1A
B) 1.5A
C) 0.26A
D) 0.10A
Show Answer
Answer:
Correct Answer: C
Solution:
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$ e_{ind}=\frac{d\phi }{dt}=\frac{d}{dt}(BA)=A\frac{dB}{dt} $
$ =A\frac{d}{dt}(4t^{2}+2t+5)=A(8t+2)=0.06(8t+2) $ =2.52 at t=5
$ \frac{i=2-e_{ind}}{2}=0.26,A $
