SATHEE: Electro Magnetic Induction And Alternating Currents Question 456

Electro Magnetic Induction And Alternating Currents Question 456

Question: A conducting circular loop is placed in a uniform magnetic field of 0.04 T with its plane perpendicular to the magnetic field. The radius of the loop starts shrinking at 2 mm/s. The induced emf in the loop when the radius is 2 cm is

Options:

A) $4.8 π μ, V$

B) $0.8 π μ, V$

C) $1.6 π μ, V$

D) $3.2 π μ, V$

Show Answer

Answer:

Correct Answer: D

Solution:

Induced emf in the loop is given by

$e = - B . \frac{d A}{d t}$ where A is the area of the loop.

$e = - B . \frac{d}{d t} (π r^{2}) = - B, π 2 r \frac{d r}{d t}$

$r = 2 c m = 2 \times 10^{- 2} m$

$d r = 2 m m = 2 \times 10^{- 3} m$ ,

$d t = 1 s$

$e = -, 0.04 \times 3.14 \times 2 \times 2 \times 10^{- 2} \times \frac{2 \times 10^{- 3}}{1} V$

$= 0.32 π \times 10^{- 5} V = 3.2 π \times 10^{- 6} V = 3.2 π μ V$

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Electro Magnetic Induction And Alternating Currents Question 456

Question: A conducting circular loop is placed in a uniform magnetic field of 0.04 T with its plane perpendicular to the magnetic field. The radius of the loop starts shrinking at 2 mm/s. The induced emf in the loop when the radius is 2 cm is

Options:

Answer:

Solution:

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