Electro Magnetic Induction And Alternating Currents Question 427

Question: A copper disc of radius 0.1 m is rotated about its centre with 10 revolutions per second in a uniform magnetic field of 0.1 Tesla with its plane perpendicular to the field. The e.m.f. induced across the radius of disc is [MH CET (Med) 2001]

Options:

A) $ \frac{\pi }{10}\ V $

B) $ \frac{2\pi }{10}\ V $

C) $ \pi \times {{10}^{-2}}V $

D) $ 2\pi \times {{10}^{-2}}V $

Show Answer

Answer:

Correct Answer: C

Solution:

$ e=\frac{1}{2}B\omega r^{2}=\frac{1}{2}\times 0.1\times 2\pi \times 10\times {{(0.1)}^{2}} $ $ =\pi \times {{10}^{-2}}V $



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