SATHEE: Electro Magnetic Induction And Alternating Currents Question 416

Electro Magnetic Induction And Alternating Currents Question 416

Question: PQ is an infinite current carrying conductor. AB and CD are smooth conducting rods on which a conductor EF moves with constant velocity v as shown. The force needed to maintain constant speed of EF is.

Options:

A) $\frac{1}{v R} {[\frac{μ_{0} I v}{2 π} I n (\frac{b}{a})]}^{2}$

B) ${[\frac{μ_{0} I v}{2 π} I n (\frac{b}{a})]}^{2} \frac{1}{v R}$

C) ${[\frac{μ_{0} I v}{2 π} I n (\frac{b}{a})]}^{2} \frac{v}{R}$

D) $\frac{v}{R} {[\frac{μ_{0} I v}{2 π} I n (\frac{b}{a})]}^{2}$

Show Answer

Answer:

Correct Answer: A

Solution:

Induced emf $\int_{a}^{b} B v d x = \int_{a}^{b} \frac{μ_{0} I}{2 π x} v d x$
$\Rightarrow$ Induced emf, $E = \frac{μ_{0} I v}{2 π} l n (\frac{b}{a})$
$\Rightarrow$ Power dissipated $= \frac{E^{2}}{R}$ Also, power $= F . v \Rightarrow F = \frac{E^{2}}{v R}$ $F = {[\frac{μ_{0} I v}{2 π} l n (\frac{b}{a})]}^{2} \frac{1}{v R}$

Play Store

App Store

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Electro Magnetic Induction And Alternating Currents Question 416

Question: PQ is an infinite current carrying conductor. AB and CD are smooth conducting rods on which a conductor EF moves with constant velocity v as shown. The force needed to maintain constant speed of EF is.

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu