Electro Magnetic Induction And Alternating Currents Question 387

Question: A coil has an area of 0.05 m2 and it has 800 turns. It is placed perpendicularly in a magnetic field of strength $ 4\times {{10}^{-5}},Wb/m^{2}, $ it is rotated through $ 90^{o} $ in 0.1 sec. The average e.m.f. induced in the coil is [CPMT 2001]

Options:

A) 0.056 V

B) 0.046 V

C) 0.026 V

D) 0.016 V

Show Answer

Answer:

Correct Answer: D

Solution:

$ e=-\frac{NBA(\cos {\theta_{2}}-\cos {\theta_{1}})}{\Delta t} $ $ =-\frac{800\times 4\times {{10}^{-5}}\times 0.05,(\cos 90^{o}-\cos 0^{o})}{0.1} $ = 0.016 V



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