Electro Magnetic Induction And Alternating Currents Question 375
Question: A circular coil of 500 turns of wire has an enclosed area of $ 0.1,m^{2} $ per turn. It is kept perpendicular to a magnetic field of induction 0.2 T and rotated by 180° about a diameter perpendicular to the field in 0.1 sec. How much charge will pass when the coil is connected to a galvanometer with a combined resistance of 50 ohms [MP PET 1997]
Options:
A) 0.2 C
B) 0.4 C
C) 2 C
D) 4 C
Show Answer
Answer:
Correct Answer: B
Solution:
$ \Delta Q=\frac{NBA}{R}( \cos {\theta_{1}}-\cos {\theta_{2}} ) $ $ =\frac{500\times 0.2\times 0.1( \cos 0-\cos 180 )}{50}=0.4\ C $
