SATHEE: Electro Magnetic Induction And Alternating Currents Question 344

Electro Magnetic Induction And Alternating Currents Question 344

Question: How much length of a very thin wire is required to obtain a solenoid of length $l_{0}$ and inductance L

Options:

A) $\sqrt{\frac{2 π L l_{0}}{μ_{0}}}$

B) $\sqrt{\frac{4 π L l_{0}}{μ_{0}^{2}}}$

C) $\sqrt{\frac{4 π L l_{0}}{μ_{0}}}$

D) $\sqrt{\frac{8 π L l_{0}}{μ_{0}}}$

Show Answer

Answer:

Correct Answer: C

Solution:

Suppose solenoid has N turns, each of radius r and length of wire is l. It’s self inductance $L = \frac{μ_{0} N^{2} A}{l_{0}} = \frac{μ_{0} N^{2} π r^{2}}{l_{0}}$ …. (i) Also length of the wire $l = N \times 2 π r$
$\Rightarrow N^{2} r^{2} = \frac{l^{2}}{4 π^{2}}$ …. (ii) From equation (i) and (ii) $l = \sqrt{\frac{4 π L l_{o}}{μ_{o}}}$

Electro Magnetic Induction And Alternating Currents Question 344

Question: How much length of a very thin wire is required to obtain a solenoid of length $l_{0}$ and inductance L

Options:

Answer:

Solution:

Engineering Preparation

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NCERT Books & Solutions

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Syllabus

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Electro Magnetic Induction And Alternating Currents Question 344

Question: How much length of a very thin wire is required to obtain a solenoid of length l0 and inductance L

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: How much length of a very thin wire is required to obtain a solenoid of length $l_{0}$ and inductance L