Electro Magnetic Induction And Alternating Currents Question 341
Question: A rectangular loop with a sliding connector of length l = 1.0 m is situated in a uniform magnetic field B = 2T perpendicular to the plane of loop. Resistance of connector is r = 2W. Two resistance of 6W and 3W are connected as . The external force required to keep the connector moving with a constant velocity v = 2m/s is
Options:
A) 6 N
B) 4 N
C) 2 N
D) 1 N
Show Answer
Answer:
Correct Answer: C
Solution:
Motional emf
$ e=Bvl\Rightarrow e=2\times 2\times 1=4\ V $
This acts as a cell of emf
$ E=4\ V $ and internal resistance $ r=2\Omega $ .
This simple circuit can be drawn as follows Current through the connector
$ i=\frac{4}{2+2}=1\ A $ magnetic force on connector
$ F_{m}=Bil=2\times 1\times 1=2\ N $ (Towards left)
