Electro Magnetic Induction And Alternating Currents Question 341

Question: A rectangular loop with a sliding connector of length l = 1.0 m is situated in a uniform magnetic field B = 2T perpendicular to the plane of loop. Resistance of connector is r = 2W. Two resistance of 6W and 3W are connected as . The external force required to keep the connector moving with a constant velocity v = 2m/s is

Options:

A) 6 N

B) 4 N

C) 2 N

D) 1 N

Show Answer

Answer:

Correct Answer: C

Solution:

Motional emf

$ e=Bvl\Rightarrow e=2\times 2\times 1=4\ V $

This acts as a cell of emf

$ E=4\ V $ and internal resistance $ r=2\Omega $ .

This simple circuit can be drawn as follows Current through the connector

$ i=\frac{4}{2+2}=1\ A $ magnetic force on connector

$ F_{m}=Bil=2\times 1\times 1=2\ N $ (Towards left)



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